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Order of Reaction

The order of ...

Question

The order of a reaction having rate constant $1.34 \times 10^{- 3}$ $m o l$ $L^{- 1} {s e c}^{- 1}$ will be:

A

0

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B

2

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C

1

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D

3

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Solution

The correct option is A $0$
Unit of rate constant is given by $m o l^{1 - n} l^{n - 1} s e c^{- 1}$
where n=order of the reaction
From the given unit, 1-n=1=> n=0
It is a zero order reaction.

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Similar questions

Q. For the reaction:

2 H_{2} + 2 N O ⇌ 2 H_{2} O + N_{2}

, the following rate data was obtained:

S. No.	$[N O]$ $m o l$ $L^{- 1}$	$[H_{2}]$ $m o l$ $L^{- 1}$	Rate: $m o l$ $L^{- 1}$ ${s e c}^{- 1}$
$1$	$0.40$	$0.40$	$4.6 \times 10^{- 3}$
$2$	$0.80$	$0.40$	$18.4 \times 10^{- 3}$
$3$	$0.40$	$0.80$	$9.2 \times 10^{- 3}$

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