Question

The order of covalent character of $KF,KI,KCl$ is :

• A. $KCl<KF<KI$
• B. $KI<KCl<KF$
• C. $KF<KI<KCl$
• D. $KF<KCl<KI$

Answer 1

The correct option is D $KF<KCl<KI$

The order of covalent character of $KF,KI,KCl$ is $KF<KCl<KI$. Greater is the electronegativity difference between cation and anion, smaller will be the covalent character.
Hence, the option (D) is the correct answer.