Question

The order of electro negativity of carbon in $sp,s{p}^{2}ands{p}^3$ hybridized states follows

• A. >>
• B. >>
• C. >>
• D. >>

Answer 1

The correct option is A >>

$HybridisationSPS{P}^{2}S{P}^3$
$\%Scharacter50\%33.33\%25\%$
More the $\%S$ character more the electronegativity [other factors being equal]
So, order of electro negativity of carbon will be,
$sp$>$s{p}^2$>$s{p}^3$