The order of heat of fusion of $T_{2}, D_{2}$ and $H_{2}$ is:

T_{2} > D_{2} > H_{2}

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H_{2} > T_{2} > D_{2}

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D_{2} > T_{2} > H_{2}

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D_{2} = T_{2} > H_{2}

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Solution

The correct option is A $T_{2} > D_{2} > H_{2}$
As we know, a very large amount of energy is needed to break bonds between $D_{2}$ because bond dissociation energy for $D_{2}$ is much higher than $H_{2}$ . This is same with $T_{2}$ as well. So that is why $H_{2}$ is more reactive than $D_{2}$ and $D_{2}$ is more reactive than $T_{2}$

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