Question

The order of -I power (-ve inductive effect ) of the following functional groups will be:

(i) $-S{O}_{3}H$

(ii) $-Cl$

(iii) $-N{H}_2$

(iv) $-H$

• A. I < II < III < IV
• B. II > III > I > IV
• C. III > II > I > IV
• D. I > II > III > IV

Answer 1

The correct option is D

I > II > III > IV

The group which withdraws electrons more will have more -I power.

$\to$ Because of full or partial positive charge directly attached to carbon, the power of -I effect varies.

Here, in case of $S{O}_{3}H$
Oxygen is more electronegative than S. Therefore, it will withdraw electrons from S making it positive.

Therefore,
-I effect will be more In $S{O}_{3}H$
$\to$ $Cl$ is one of the most E.N. atom

$\to$ Therefore

$-S{O}_{3}H>-Cl>-N{H}_2>-H$