The order of increasing acidic nature for $S O_{2}, S i O_{2}, P_{2} O_{3}, A l_{2} O_{3}$ is:

S O_{2} < P_{2} O_{3} < S i O_{2} < A l_{2} O_{3}

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A l_{2} O_{3} < S i O_{2} < P_{2} O_{3} < S O_{2}

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A l_{2} O_{3} < S i O_{2} < S O_{2} < P_{2} O_{3}

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S i O_{2} < S O_{2} < A l_{2} O_{3} < P_{2} O_{3}

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Solution

The correct option is B $A l_{2} O_{3} < S i O_{2} < P_{2} O_{3} < S O_{2}$
The acidic character of oxides of elements increases as we move from left to right in a period of the modern periodic table. From the given oxides $S O_{2}$ is highly acidic in nature, $S i O_{2}$ weakly acidic in nature, $P_{2} O_{3}$ is acidic in nature, $A l_{2} O_{3}$ is amphoteric in nature.

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