The order of increasing bond length in $F_{2}, N_{2}, C l_{2}$ and $O_{2}$ is :

N_{2} < O_{2} < C l_{2} < F_{2}

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N_{2} < O_{2} < F_{2} < C l_{2}

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O_{2} < N_{2} < C l_{2} < F_{2}

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N_{2} < C l_{2} < O_{2} < F_{2}

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Solution

The correct option is C $N_{2} < O_{2} < F_{2} < C l_{2}$
Bond length depends on bond order.
$N_{2}$ = 3
$O_{2}$ = 2
$F_{2}$ and $C l_{2}$ = 1, but $C l$ is bigger than $F$ .

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Similar questions

N_{2}, O_{2}, C l_{2}, F_{2}

F_{2} < {C l}_{2} < O_{2} < N_{2}

N_{2}^{+}

N_{2}

O_{2}^{+}

O_{2}

N_{2}

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N_{2}^{+}

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What is the effect of the following processes on the bond order in $N_{2}$ and $O_{2}$ ?

(i). $N_{2} \to N_{2}^{+} + e^{-}$

(ii) $O_{2} \to O_{2}^{+} + e^{-}$

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