Question

The order of magnitude of revolution period of the earth around the sun is

• A. ${10}^{4}s$
• B. ${10}^{5}s$
• C. ${10}^{7}s$
• D. ${10}^{8}s$

Answer 1

The correct option is C ${10}^{7}s$

The time period of the revolution of the earth around the sun is $365$ days.

In seconds it is given as $365\times 24\times 60\times 60=31536000$ seconds.

Converting it into scientific notation =$3.15\times {10}^{7}s$

To convert it into the order of magnitudes, we need to see that the number is either greater than $5$ or less than $5$. Since, $3.15$ is less than $5$, we will leave the powers of $10$ unchanged.

$\therefore$ Order of magnitude = ${10}^7$