The order of reactivity of alkyl halides is as follows:

R C l < R B r < R I

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R I < R B r > R C l

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R B r > R I > R C l

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R I > R C l > R B r

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Solution

The correct option is A $R C l < R B r < R I$
Iodide is the best leaving group.
Leaving group order: iodide > bromide > chloride > fluoride
Hence, the reactivity order is $R I > R B r > R C l$ .

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The order of reactivity of the following alkyl halides for an SN² reaction is

The order of reactivity of haloalkenes is RI>RCl>RBr

Why

R I > R B r > R C l > R F

R I > R B r > R C l > R F

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