You visited us 1 times! Enjoying our articles? Unlock Full Access!

Dehydration of Alcohols

The order of ...

Question

The order of reactivity of following alcohols with halogen acids is:
I. $C H_{3} C H_{2} C H_{2} O H$

II. $C H_{3} C H_{2} - C | H O H - C H_{3}$

III. $C H_{3} C H_{2} - C H_{3} | C | C H_{3} - O H$

II > I > III

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I > III > II

No worries! We‘ve got your back. Try BYJU‘S free classes today!

III > II > I

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

I > II > III

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B III > II > I
Reactivity of alcohols towards halogen acids decreases in the order:
$3^{o} > 2^{o} > 1^{o}$ i.e., $I I I > I I > I$

Since the tertiary carbocation formed is most stable than primary and secondary carbocation.

Suggest Corrections

Similar questions

C H_{3} C H_{2} - C H_{2} - O H

C H_{3} C H_{2} - (C H_{3}) C H - O H

C H_{3} C H_{2} - C H_{3} | C | C H_{3} - O H

H - X

C H_{2} = C H - O H

C H_{2} = C H - C H_{2} O H

C H_{3} - C H_{2} - O H

C H_{3} - C H | O H - C H_{3}

P h O^{⊖}

C H_{3} S^{⊖}

⊖ O H

M e O^{⊖}

C H_{2} = O H | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O H | C = C H - O | | C - C H_{3}

I

I I

I I I

C H_{2} = O H | C - C H_{2} (I) - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} (I I) - O | | C - C H_{3}

⇌ C H_{3} - O H | C = C H (I I I) - O | | C - C H_{3}

Join BYJU'S Learning Program