The order of stability of three alkenes RCH=CHR,R2C=CHR and R2C=CR2 is :
A
RCH=CHR>R2C=CHR>R2C=CR2
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B
RCH=CHR<R2C=CHR>R2C=CR2
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C
RCH=CHR>R2C=CHR<R2C=CR2
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D
RCH=CHR<R2C=CHR<R2C=CR2
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Solution
The correct option is DRCH=CHR<R2C=CHR<R2C=CR2 Highly substituted alkenes are more stable. Thus, the order of stability will be: CR2=CR2>R2C=CHR>CHR=CHR