The order of successive ionization energies x- y and z of an element is x- What could be the number of valence electrons in the atom of the element-

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Question

The order of successive ionization energies x, y and z of an element is $x<y<z$ . What could be the number of valence electrons in the atom of the element?

$1$

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$2$

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$3$

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Solution

The correct option is B
$2$

Explanation for correct option: (b)
The Ionization energy of an element represents the energy required to remove electrons from an atom.
The second ionization energy is greater than the first ionization energy because it is more difficult to remove an electron from a positively charged ion than from a neutral atom.
Similarly, successive ionization energies like third, fourth, etc. will be also higher than the first.
Here ‘x’ indicates the first ionization energy, ‘y’ indicates the second ionization energy after the removal of one electron and ‘z’ indicates the third ionization energy after the removal of two electrons.
Hence the total number of valence electrons present in the element is $2$ .
Explanation for incorrect options:
a) The total number of valence electrons present in the atom of the element is $2$ not $1$ .
c) The given option is not correct. The total number of valence electrons present in the atom of the element is $2$ .
d) If the order of ionization energies of the elements is $x<y<z$ , then the total number of valence electrons present in the atom of the element is $2$ .
Hence option (b) is correct and the total number of valence electrons present in the atom of the element is $2$ .

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The order of successive ionization energies x, y and z of an element is x<y<z. What could be the number of valence electrons in the atom of the element?

The order of successive ionization energies x, y and z of an element is $x<y<z$ . What could be the number of valence electrons in the atom of the element?