Question

The order of the bond angles in the following molecule is:

• A. ${\theta }_1>{\theta }_3>{\theta }_2$
• B. ${\theta }_2>{\theta }_1>{\theta }_3$
• C. ${\theta }_3>{\theta }_2>{\theta }_1$
• D. ${\theta }_2>{\theta }_3>{\theta }_1$

Answer 1

The correct option is A ${\theta }_1>{\theta }_3>{\theta }_2$

The repulsions between double bonds is more in comparison to the repulsion between a double bond and a single bond which in turn is more than the repulsion between a single bond and a single bond. More the repulsion, more will be the bond angle. Hence, option A is correct.