The order of the differential equation d 2 y d x 2 - 1- dy dx 2 is

The correct option is D 2 Given differential equation is d ^ 2 y d x ^ 2 =√( 1+( dy dx nbsp;) nbsp;^ 2 ) ⇒( d ^ 2 y d x ^ 2 nbsp;) ...

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Order of a Differential Equation

The order of ...

Question

The order of the differential equation $\frac{d^{2} y}{d x^{2}} = \sqrt{1 + {(\frac{d y}{d x})}^{2}}$ is

3

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2

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1

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4

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\frac{d^{2} y}{d x^{2}} - {(\frac{d y}{d x})}^{2} = 1

\frac{d^{2} y}{d x^{2}} = {[1 + {(\frac{d y}{d x})}^{2}]}^{\frac{3}{2}}

{[1 + {(\frac{d y}{d x})}^{2} + sin (\frac{d y}{d x})]}^{3 / 4} = \frac{d^{2} y}{d x^{2}}

The order and degree of the differential equation ${[4 + {(\frac{d y}{d x})}^{2}]}^{2 / 3} = \frac{d^{2} y}{d x^{2}}$ are

{[1 + {(\frac{d y}{d x})}^{2}]}^{3} = C^{2} {[\frac{d^{2} y}{d x^{2}}]}^{2}

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