The order of the oxidation state of the phosphorus atom in $H_{3} P O_{2}, H_{3} P O_{4}, H_{3} P O_{3}$ and $H_{4} P_{2} O_{6}$ is:

H_{3} P O_{4} > H_{4} P_{2} O_{6} > H_{3} P O_{3} > H_{3} P O_{2}

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H_{3} P O_{2} > H_{3} P O_{3} > H_{4} P_{2} O_{6} > H_{3} P O_{4}

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H_{3} P O_{4} > H_{3} P O_{2} > H_{3} P O_{3} > H_{4} P_{2} O_{6}

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H_{3} P O_{3} > H_{3} P O_{2} > H_{3} P O_{4} > H_{4} P_{2} O_{6}

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Solution

The correct option is B $H_{3} P O_{4} > H_{4} P_{2} O_{6} > H_{3} P O_{3} > H_{3} P O_{2}$
Correct order :
$H_{3} P O_{4} > H_{4} P_{2} O_{4} > H_{3} P O_{3} > H_{3} P O_{3}$
$(+ 5)$ $(+ 4)$ $(+ 3)$ $(+ 1)$

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Similar questions

H_{3} P O_{2}, H_{3} P O_{4}, H_{3} P O_{3}

H_{4} P_{2} O_{6}

H_{3} P O_{2}, H_{3} P O_{4}, H_{3} P O_{3}

H_{4} P_{2} O_{6}

H_{3} P O_{4}, H_{3} P O_{3}, H_{3} P O_{2}, H C l O, H_{4} P_{2} O_{6}, H_{2} S_{2} O_{6}

H_{3} P O_{2}, H_{3} P O_{3}

H_{3} P O_{4}

H_{3} P O_{2}, H_{3} P O_{3}

H_{3} P O_{4}

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