The order of volume of gases $N H_{3}, C O_{2}$ and $C H_{4}$ adsorbed by one gram of charcoal at 298 K, is:

C H_{4} > C O_{2} > N H_{3}

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N H_{3} > C H_{4} > C O_{2}

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N H_{3} > C O_{2} > C H_{4}

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C O_{2} > N H_{3} > C H_{4}

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Solution

The correct option is C $N H_{3} > C O_{2} > C H_{4}$
Easily liquifiable gases absorb to a greater extent. Therefore, the order is given by:

$N H_{3} > C O_{2} > C H_{4}$ , as $N H_{3}$ is easily liquifiable followed by $C O_{2}$ and $C H_{4}$ at the last.

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