The ordinate of a point is twice its abscissa. If its distance from the point (4,3) is , then the coordinates of the point are
(1,2) or (3,6)
Let the coordinates of the point be P(x,2x). Let Q be the point (4,3).
PQ2=(4-x)2+(3-2x)2 = 10
16+x2-8x+9+4x2-12x=10
5x2-20x+15=0
x2-4x+3=0
(x-3)(x-1)=0
x=1 or x=3
So, 2x = 2 or 6
Hence, the coordinates of the required point are (1,2) or (3,6).