The ordinates of a two hour unit hydrograph at sixty minutes time interval starting from time t = 0 are 0,1.5,5.5,10,9,4.5,1.5 and 0m3/s . The maximum ordinate of one hour unit hydrograph would be __________ [Rounded upto two decimal places]
12
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Solution
The correct option is A 12 Time2−hrLag 2 hrSA−CurveSB−CurveSA−SBOrdinate of 1-hr UHUHS-curve AdditionLag-1hr=SA−SB(1/2)×1cm00−0−0011.5−1.501.5325.505.51.5483101.511.55.5612495.514.511.53654.511.51614.51.5361.514.51616007016161600