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Question

The ordinates of the foot of normal(s) to the parabola y2=4ax from the point (6a,0) is/are


A
0
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B
4a
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C
2a
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D
2a
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Solution

The correct options are
A 0
B 4a
Normal to y2=4ax is
y+tx=at3+2at
Since (6a,0) lies on it, so 
0+6at=at3+2at6t=t3+2t  (a0)t(t2)(t+2)=0t=2,0,2

Coordinates of foot of normal are
(at21,2at1),(at22,2at2),(at23,2at3)(4a,4a),(0,0),(4a,4a)

Ordinates are 4a,0,4a

Mathematics

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