The possible routes are -
RouteTotal TimeJunctionS−A−T14AS−B−A−T9A,BS−B−C−T7B,CS−D−C−T10C,DS−D−T13D
It is given that, for each of the routes, the only way to increase the total time is to impose task time at the junctions. Let the task time at A, B, C, D be a, b, c, d hours respectively.
Now, the total time for each of the five routes will be as follows.
RouteTotal TimeS−A−T14+aS−B−A−T9+(a+b)S−B−C−T7+(b+c)S−D−C−T10+(c+d)S−D−T13+d
There must be another route other than those involving B with the least time as at most only 70% participants can use this route.
Also, the other route should take time equal to the route through B. The minimum time for the other route will be through route S-D-C-T which is 10 hours (if task time at C and D is 0).
In that case, for route S-B-C-T, the total time = 10 hours (if task time at B = 3 hours).
∴ 10 hours is the least time.