The origin is shifted to the point $(- 5, 9)$ axes remaining parallel, If the point $(3, b)$ lies on the new x-axis and the point $(a, 3)$ lies on the new y-axis. Find the value of $a$ and $b$ .

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Solution

Origin $(- 5, 9)$
Axes will become, $x - a x i s => y = 9$
$y - a x i s => x = - 5$
For point $(3, b)$ on x-axis =>ordinate, $b = 9$ (as $y = 9)$
for point $(9, 3)$ on y-axis absscicca, $a = - 5$ (as $x = - 5)$

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The origin is shifted to the point (−5,9) axes remaining parallel, If the point (3,b) lies on the new x-axis and the point (a,3) lies on the new y-axis. Find the value of a and b.

Origin (−5,9)Axes will become, x−axis=>y=9 y−axis=>x=−5For point (3,b) on x-axis =>ordinate, b=9 (as y=9)for point (9,3) on y-axis absscicca, a=−5 (as x=−5)

The origin is shifted to the point $(- 5, 9)$ axes remaining parallel, If the point $(3, b)$ lies on the new x-axis and the point $(a, 3)$ lies on the new y-axis. Find the value of $a$ and $b$ .

Origin $(- 5, 9)$
Axes will become, $x - a x i s => y = 9$
$y - a x i s => x = - 5$
For point $(3, b)$ on x-axis =>ordinate, $b = 9$ (as $y = 9)$
for point $(9, 3)$ on y-axis absscicca, $a = - 5$ (as $x = - 5)$