The orthocentre of a triangle formed by the lines x−2y=1,x=0 and 2x+y−2=0 is
A
(0,1)
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B
(1,0)
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C
(−1,−2)
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D
(1,2)
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E
(0,0)
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Solution
The correct option is B(1,0) Given equations of lines are x−2y=1,x=0 and 2x+y−2=0 From figure, Since, AB is perpendicular to AC. So, orthocentre is the meeting point of AB and AC, i.e., (1,0).