Question

The orthocentre of the triangle formed by 0(0, 0), A(1, 0), B(0, 1), where orthocentre is the point of intersection of altitudes drawn from vertices on opposite sides is

• A. $(\frac{1}{2},\frac{1}{2})$
• B. $(\frac{1}{3},\frac{1}{3})$
• C. $(0,0)$
• D. $(\frac{1}{4},\frac{1}{4})$

Answer 1

The correct option is C $(0,0)$

Given a $\Delta OAB$, which is a right-angled triangle at vertex $O$.

Also in right-angled triangle the orthocentre lies on the vertex which forms right angle.

So the orthocentre of $\Delta OAB$ is $(0,0)$.