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Question

The oscillator has energy of oscillations E. If the mass of oscillator is doubled the energy now for same oscillation amplitude becomes

A
E / 2
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B
E / 4
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C
E
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D
2 E
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Solution

The correct option is D E
Energy of oscillator is given by E=12mw2A2
Time period of the oscillation T=2πmK
T2π=mKw=Km
Thus E=12m×Km×A2
E=12KA2 which states that energy is independent of mass of the oscillator.
Thus for same oscillation amplitude, energy of oscillator will remain the same.

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