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Standard XII

Chemistry

Osmotic Pressure

The osmotic p...

Question

The osmotic pressure of 400 ml urea and 600 ml glucose solutions are respectively 0.3 atm and 0.4 atm. The osmotic pressure of the solution obtained by mixing them will be?

0.24

atm

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0.36

atm

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0.48

atm

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0.52

atm

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Solution

The correct option is B $0.36$ atm
$Π = \frac{0.3 \times 400 + 0.4 \times 600}{400 + 600}$
$= \frac{120 + 240}{1000}$
$= \frac{360}{1000} = 0.36$
Osmotic pressure= $0.36 a t m$ .

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The osmotic pressure of 400 ml urea and 600 ml glucose solutions are respectively 0.3 atm and 0.4 atm. The osmotic pressure of the solution obtained by mixing them will be?

The correct option is B 0.36 atmΠ=0.3×400+0.4×600400+600 =120+2401000=3601000=0.36Osmotic pressure= 0.36atm .

The correct option is B $0.36$ atm
$Π = \frac{0.3 \times 400 + 0.4 \times 600}{400 + 600}$
$= \frac{120 + 240}{1000}$
$= \frac{360}{1000} = 0.36$
Osmotic pressure= $0.36 a t m$ .