The osmotic pressure of a $5 %$ solution of cane sugar (molecular mass 342) at $15^{o} C$ is:

3.46 atm

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3.64 atm

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4.0 atm

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2.45 atm

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Solution

The correct option is D 3.46 atm
$m$ = mol. mass of sucrose $= 342$

$w$ = $5 g .$ $V$ = $100 m L = 0.1 l i t r e$
$S = 0.082,$ $T = (15 + 273) = 288 K$

Applying the equation $P V = \frac{w}{m} S T,$

$P = \frac{5}{342} \times \frac{1}{0.1} \times 0.082 \times 288$

$= 3.453 a t m$

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