Question

The osmotic pressure of a solution at $0^{\circ }C$ is $4atm$. What will be its osmotic pressure at $546K$ under similar conditions?

• A. $2atm$
• B. $6atm$
• C. $8atm$
• D. $4atm$

Answer 1

The correct option is C $8atm$

Osmotic pressure $\left(\pi \right)$ is given by
$\pi =CRT$
where
$C\text{is the concentration (molarity)}R\text{is ideal gas constant}T\text{is temperature}$
Condition 1:
When temperature is $0^{\circ }C=273K$
${\pi }_1=C\times R\times 273..eq\left(i\right)$

Condition 2:
When temperature is $546K$
${\pi }_2=C\times R\times 546..eq\left(ii\right)$
Dividing both the equations:

$\frac{{\pi }_1}{{\pi }_2}=\frac{C\times R\times 273}{C\times R\times 546}\frac{4}{{\pi }_2}=\frac{273}{546}{\pi }_2=8atm$