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System, Surroundings, Intensive, Extensive Properties

The osmotic p...

Question

The osmotic pressure of a solution (density is $1 g m L^{- 1}$ ) containing 3 g of glucose (molecular weight = 180) in 60 g of water at $15^{\circ} C$ is

0.34 atm

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0.65 atm

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6.25 atm

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5.57 atm

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Solution

The correct option is C 6.25 atm
$π \times \frac{63}{1000} = \frac{3}{180} \times 0.0821 \times 288 ∴ π = 6.25 a t m ∵ V_{s o l u t i o n} = W e i g h t o f s o l u t i o n \times D e n s i t y$

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Similar questions

1 g {m L}^{- 1}

3 g

= 180

60 g

15^{o} C

If 3 gm of glucose (mol. wt. 180) is dissolved in 60 gm of water at 15⁰C. Then the osmotic pressure of this solution will be

5 %

25^{o} C

= 180

R = 0.0821

K^{- 1} m o l^{- 1}

15^{o} C

(i n a t m)

0.5 M

127^{\circ} C

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