The osmotic pressure of equimolar solutions of BaCl $_{2}$ , NaCl and glucose will be in the order:

g l u c o s e

> N a C l > B a C l_{2}

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B a C l_{2} > N a C l >

g l u c o s e

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N a C l > B a C l_{2} >

g l u c o s e

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N a C l >

g l u c o s e

> B a C l_{2}

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Solution

The correct option is B $B a C l_{2} > N a C l >$ $g l u c o s e$
Osmotic pressure is a colligative property, and more the number of particles more the osmotic pressure.

$π = i C R T$

Hence, $B a C l_{2} > N a C l > G l u c o s e$ since the concentration is same and $i$ for $B a C l_{2}$ is 3, $N a C l$ is 2 and glucose is 1.

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B a C l_{2}

A l F_{3}

0.1 M

N a C l

0.1 M

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