The osmotic pressure of equimolar solutions of urea, BaCI2 and AlCI3 will be in the order:

A l C l_{3} > B a C l_{2} >

Urea

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B a C l_{2} > A l C l_{3} >

Urea

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U r e a > B a C l_{2} > A l C l_{3}

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B a C l_{2} > U r e a > A l C l_{3}

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Solution

The correct option is A $A l C l_{3} > B a C l_{2} >$ Urea
As we know,
Osmotic pressure = iCRT
so higher the no of ions, higher will be osmotic pressure.
$A l C l_{3} (i = 4), B a C l_{2} (i = 3), U r e a (i = 1)$
So order is
$A l C l_{3} > B a C l_{2} >$ Urea

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The osmotic pressure of equimolar solutions of urea, BaCl2 and AlCl3 will be in the order-

3 m

N a_{2} S O_{4}

1 m

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B a C l_{2} + A l (s o_{4})_{3} \Rightarrow A l C l_{3} + B a S o_{4}

In equimolar solution of glucose, NaCl and BaCl₂, the order of osmotic pressure is as follows:

0.1M of urea is isotonic to

a)0.1M NaCl solution

b) 0.1M glucose solution

C)0.02M KCl solution

d) 0.1 BaCl2 solution

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