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Standard XII
Chemistry
Enzymes
The osmotic p...
Question
The osmotic pressure of two aqueous urea solutions-I and II are
2.1
a
t
m
and
1.8
a
t
m
respectively at
25
∘
C
. The osmotic pressure (in atm) of a solution at
25
∘
C
prepared by mixing solution I and II in the volume ratio of
2
:
1
is
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Solution
Osmotic pressure
(
π
)
=
i
C
R
T
i
=
1
π
1
=
C
1
R
T
⟹
C
1
=
2.1
R
T
C
2
=
1.8
R
T
C
(no mixing)
=
(
2.1
×
2
R
T
+
1.8
R
T
)
×
1
3
=
2
R
T
∴
π
=
C
R
T
=
2
R
T
×
R
T
=
2
a
t
m
.
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Similar questions
Q.
100 mL aqueous solution of glucose with osmotic pressure 1.2 atm at
25
o
C
is mixed with 300 mL aqueous solution of urea at 2.4 atm at
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. Calculate the osmotic pressure of mixture.
Q.
The osmotic pressure of 400 ml urea and 600 ml glucose solutions are respectively 0.3 atm and 0.4 atm. The osmotic pressure of the solution obtained by mixing them will be?
Q.
Osmotic pressure of
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t
m
. and that of
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Find out the osmotic pressure
(
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t
m
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for
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Q.
The osmotic pressure of 40% (weight/volume) urea solution is 1.64 atm and that of 3.42% (weight/volume) cane sugar is 2.46 atm. When equal volumes of the above two solutions are mixed, the osmotic pressure of the resulting solution is:
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