Question

The outer area of the given wooden box needs to be painted. Find the surface area of the box to be painted.

• A. 468 sq in
• B. 568 sq in
• C. 378 sq in
• D. 140 sq in

Answer 1

The correct option is B 568 sq in

The given box is in the form of a rectangular prism.

It has 6 faces.

Total surface area = 2 $\times$(surface area of A +surface area of side B + surface area of side C)

Surface area of side A = length $\times$ width

Length of side A = 14 in

Width of side A = 6 in

Surface area of A = 14 $\times$ 6 = 84 sq in



Surface area of side B = length $\times$ width

Length of side B = 14 in

Width of side B = 10 in

Surface area of B = 14 $\times$ 10 = 140 sq in



Surface area of side C = length $\times$ width

Length of side C = 10 in

Width of side C = 6 in

Surface area of C = 10 $\times$ 6 = 60 sq in


Total surface area = 2$\times$(surface area of A+ surface area of side B + surface area of side C)

= 2$\times$(84+140+60) = 2$\times$284

= 568 sq in

Hence, the total surface area = 568 sq in.