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Question

The outer area of the given wooden box needs to be painted. Find the surface area of the box to be painted.


A
460 sq in
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B
268 sq in
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C
140 sq in
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D
568 sq in
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Solution

The correct option is D 568 sq in
The given box is in the form of a cuboid.

It has 6 faces.


Total surface area = 2 ×(surface area of A +surface area of side B + surface area of side C)

Surface area of side A = length × width

Length of side A = 14 in

Width of side A = 6 in

Surface area of A = 14 × 6 = 84 sq in



Surface area of side B = length × width

Length of side B = 14 in

Width of side B = 10 in

Surface area of B = 14 × 10 = 140 sq in



Surface area of side C = length × width

Length of side C = 10 in

Width of side C = 6 in

Surface area of C = 10 × 6 = 60 sq in

Total surface area = 2×(surface area of A+ surface area of side B + surface area of side C)

= 2×(84+140+60) = 2×284

= 568 sq in

Hence, total surface area = 568 sq in.


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