Question

The outer circumference of a circle track is $196.68m$ and the track is everywhere $6m$ side. Find the cost of levelling the track at the rate of $25$ paise per $m^2$.[Take $\pi =3.14$]

Answer 1

$2\pi R=196.68m$

$R=\frac{196.68}{2\times 3.14}=31m$

$r=R-6=25$m

Area of Track $=\pi [R^2-r^2]$

$=3.14\left(336\right)$

$=1055.04$

cost $=1055.04\times \frac{25}{100}$

$=263.76$Rs.