The outermost electronic configuration of the most electronegative element is:

{n s}^{2} {n p}^{3}

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{n s}^{2} {n p}^{4}

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{n s}^{2} {n p}^{5}

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{n s}^{2} {n p}^{6}

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Solution

The correct option is D ${n s}^{2} {n p}^{5}$
${n s}^{2} {n p}^{5}$ configuration represents the most electronegative element as after gaining one electron it becomes more stable (inert gas configuration) [electronegativity is the tendency of attracting electron].
Fulorine (atomic number 9) is the most electronegative element. Its electronic configuration is $1 s^{2} {2 s}^{2} {2 p}^{5}$ . It is a halogen.

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Similar questions

Q. Two p-block elements

x

having (outer shell configuration ns

^{2}

,np

^{3}

and

z

(outer shell configuration ns

^{2}

,np

^{4}

) occupy neighbouring positions in a period. Using this information which of the following is correct with respect to their ionization potential as

I_{x}

and

I_{z}

Two p-block elements x(outer electronic configuration ${n s}^{2}$ , ${n p}^{3}$ ) and z (outer configuration ${n s}^{2}$ , ${n p}^{4}$ ) occupy neighbouring positions in a period. Using this information which of the following is correct with respect to their ionisation potential $I_{x}$ and $I_{z}$ .