The outermost electronic configuration of the most electronegative elements is

2 s^{2} 2 p^{3}

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2 s^{2} 2 p^{4}

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2 s^{2} 2 p^{5}

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2 s^{2} 2 p^{6}

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Solution

The correct option is C $2 s^{2} 2 p^{5}$
The most electronegative element is Fluorine and has a configuration of $n s^{2} n p^{5}$ . After gaining one elecron it will attain the inert gas configuration and becomes highly stable.
Fluorine having atomic number of 9 has a configuration $1 s^{2} 2 s^{2} 2 p^{5}$

The correct option is (c).

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Question 21

The electronic configuration of the outer most shell of the most electronegative elements is

(a) $2 s^{2} 2 p^{5}$

(b) $3 s^{2} 3 p^{5}$

(d) $5 s^{2} 5 p^{5}$

1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 3 d^{10}, 4 s^{1}

1 s^{2}, 2 s^{2}, 2 p^{5}

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