Question

The output current versus time curve for a rectifies is shown in the figure. The average value of output current in this case is

• A. $0$
• B. $\frac{I_0}{2}$
• C. $\frac{2I_0}{\pi }$
• D. $l_0$

Answer 1

The correct option is C $\frac{2I_0}{\pi }$

The average value of output

$={}_0^{I/2}\int I.dt$

$I=I_0\sin wt$

$=\frac{2I_0}{\pi }$