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Question

The output of an OR gate is connected to both the inputs of a NAND gate. The combination will serve as:

A
AND gate
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B
NOT gate
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C
NAND gate
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D
NOR gate
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Solution

The correct option is D NOR gate
Let inputs be A and B.
Then, output of OR gate is Y=A+B

The above output is fed to both the inputs of NAND gate. Hence, output of NAND gate is:
Z=¯¯¯¯¯¯¯¯¯¯¯¯YY=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(A+B)(A+B)=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯A+B
Hence, combination serves as NAND gate.

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