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Question

The output of the circuit shown in figure is equal to


A
¯AB+A¯B
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B
1
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C
(¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯AB)(¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯AB)
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D
0
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Solution

The correct option is B 1
Y=(A¯B)(¯AB)
Y=A¯B¯AB
Y=(A¯A)(¯BB)
Y=00
Y=1

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