Question

The output 'Y' of the multiplexer circuit shown in figure below is

• A. $A⨁B$
• B. $A⨁B⨁C$
• C. $A⨀B$
• D. $\overline{A}\overline{B}C+ABC+\overline{A}BC+AB\overline{C}$

Answer 1

The correct option is B $A⨁B⨁C$

The output of the MUX will be,

$Y=\overline{B}\overline{A}C+\overline{B}A\overline{C}+B\overline{A}\overline{C}+BAC$

$=\overline{C}(\overline{A}B+A\overline{B})+C(\overline{A}\overline{B}+AB)$

$=\overline{C}(A⨁B)+C(A⨀B)$

$=(A⨁B)\overline{C}+C\left(\overline{A⨁B}\right)$

$Y=A⨁B⨁C$