Question

The overall reaction in the sun responsible for the energy it radiates is
$4{(}_1^{1}H){⟶}_2^{4}He+2_1^{0}e({\beta }^{+})$
It has been estimated that the sun produces $3\times {10}^{22}kJ{s}^{-1}$. How many moles of H-atoms are converted to He in 1 second, to produce this energy? (Take binding energy 27 MeV)

• A. $4.61\times {10}^{13}$ mol H atoms $s^{-1}$
• B. $3.68\times {10}^{13}$ mol H atoms $s^{-1}$
• C. $5.71\times {10}^{13}$ mol H atoms $s^{-1}$
• D. None of these

Answer 1

Answer: (D)

None of these

$4{(}_1^{1}H){⟶}_2^{4}He+2_1^{0}e({\beta }^{+})+27MeV$

4 mole of hydrogen atoms gives 27 MeV energy.

No of moles of hydrogen atom converted to produce $3\times {10}^{22}kJ$ is $=\frac{4\times 3\times {10}^{22}}{27\times 1.6\times {10}^{-16}}=4.61\times {10}^{37}$ mol H atom per sec.