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Question

The oviline series of minerals consists of crystals in which Fe and Mg ions may substitute for each other causing substitutional impurity defect without changing the volume of the unit cell. In oviline series of minerals, oxide ion exists as FCC with Si4+ occupying 1/4th of octahedral voids and divalent ions occupying 1/4th of tetrahedral voids. The density of foresite (magnesium silicate) is 3.21 g/cc and that of fayalite (ferrous silicate) is 4.34 g/cc. Find the formula of forsterite and fayalite minerals and the percentage of fayalite in an olivine with a density of 3.88 g/cc.

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Solution

Zeff of O2=4
Zeff of Si+4=18×4=1
Zeff of divalent ion (Fe or Mg)=14×8=2
General Formula M2SiO4
Forsterite=Mg2SiO4 Fayalite:Fe2SiO4

(B) Let fraction of fayalite be x and fraction of forsterite be 1x
3.88=4.34x+3.21(1x)
0.67=1.13xx=0.593
Therefore, percentage of fayalite =59.3%

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