The oxidation number and coordination number of chromium in the following complex is:
${[C r {(C_{2} O_{4})}_{2} {(N H_{3})}_{2}]}_{2}^{- 1}$

O . N . = + 4, C . N . = 4

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O . N . = + 3, C . N . = 4

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O . N . = - 1, C . N . = 4

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O . N . = + 3, C . N . = 6

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Solution

The correct option is D $O . N . = + 3, C . N . = 6$
$[C r (C_{2} O_{4})_{2} (N H_{3})_{2}]^{1}$ .
As here Cr is connected with 6 ligands (2 oxo+2 ammonia) so its coordination no. is 6.Here, $C r^{+ 3}, d^{3}$ configuration.

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