Question

The oxidation number and coordination number, of copper in $\left[Cu\right(N{H}_3{)}_4{]}^{2+}$ are:

• A. 4 and 2
• B. 1 and 3
• C. 2 and 4
• D. 3 and 1

Answer 1

Answer: (C)

2 and 4

Since copper is surrounded by four ammonia group hence its coordination number is 4.

Now, oxidation number of copper is given as:

$x+0=+2$ i.e. $x=+2$

Hence, the oxidation number of copper in the given complex is +2.

Option C is correct.