The oxidation number for sulfur is highest in which of the following ions or compounds?

S O_{2}

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S O_{3}^{2 -}

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S O_{4}^{2 -}

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S_{2} O_{3}^{2 -}

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H S O_{3}^{-}

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Solution

The correct option is C $S O_{4}^{2 -}$
$S O_{4}^{2 -} : x + (- 2 \times 4) = - 2$
$\Rightarrow x - 8 = - 2$
$\Rightarrow x = - 2 + 8$
$\Rightarrow x = 6$ .

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(S_{2} O_{3}^{2 -})

{S O}_{3}^{2 -}, {S O}_{4}^{2 -}, S_{2} O_{4}^{2 -}, S_{2} O_{6}^{2 -}

S

{H S O_{3}}^{-}

M n O_{4}^{-} + H S O_{3}^{-} \to M n O_{4}^{2 -} + S O_{4}^{2 -}

C O_{3}^{2 -}

S O_{3}^{2 -}

S O_{4}^{2 -}

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