Question

The oxidation number of $C$ in $C{H}_{2}O$ is :

• A. $-2$
• B. $+2$
• C. $0$
• D. $+4$

Answer 1

Answer: (C)

$0$

Let $x$ be the oxidation state of $C$ in $C{H}_{2}O$.
Since, the overall charge on the complex is $0$, the sum of oxidation states of all elements in it should be equal to $0$.
Therefore,
$x+2-2=0$
or, $x=0$.
Hence, the oxidation state of $C$ in $C{H}_{2}O$ is $0$.