The oxidation number of C in $C H_{4}, C H_{3} C l, C H_{2} C l_{2}, C H C l_{3}$ and $C C l_{4}$ is respectively:

-4, -2, 0, +2, +4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

+2, 4, 0, -2, -4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4, 2, 0, -2, 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0, 2, -2, 4, 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C -4, -2, 0, +2, +4
$H = + 1$ $C l = - 1$

$C H_{4}$ $C H_{3} C l$ $C H_{2} C l_{2}$
$x + 4 = 0$ $x + 3 - 1 = 0$ $x + 2 - 2 = 0$
_____ _ __________
$x = - 4$ $x = - 2$ $x = 0$

$C H C l_{3}$ $C C l_{4}$
$x + 1 - 3 = 0$ $x - 4 = 0$
_
$x = + 2$ $x = + 4$

Suggest Corrections

Similar questions

Q. The oxidation numbers of C in

C H_{4}, C H_{3} C l, C H_{2} C l_{2}, C H C l_{3}

and

C C l_{4}

are respectively.

Q. Regarding dipole moment of the following species.

C H_{4}, C H_{3} C l, C H_{2} C l_{2}, C H C l_{3}, C C l_{4}

Zero :

C C l_{4}

Maximum :

C H_{3} C l

Order being :

C H_{4} = C C l_{4} < C H C l_{3} < C H_{2} C l_{2} < C H_{3} C l

If true enter 1, else enter 0.

Following data gives the number of children in 40 families:
1, 2, 6, 5, 1, 5, 1, 3, 2, 6, 2, 3, 4, 2, 0, 4, 4, 3, 2, 2, 0, 0, 1, 2, 2,4,3,2, 0, 5, 1, 2, 4, 3, 4, 1, 6, 2, 2.
Represent it in the form of a frequency distribution, taking classes 0-2,2-4, etc.

Q. The oxidation number of sulphur in

S_{8}, S_{2} F_{2}, H_{2} S

respectively are.

Q. Question 10
Which of the following equations has no real roots?
(A)

x^{2} - 4 x + 3 \sqrt{2} = 0

(B)

x^{2} + 4 x - 3 \sqrt{2} = 0

(C)

x^{2} - 4 x - 3 \sqrt{2} = 0

(D)

3 x^{2} - 44 \sqrt{3} x + 4 = 0

Join BYJU'S Learning Program

The oxidation number of C in CH4,CH3Cl,CH2Cl2,CHCl3 and CCl4 is respectively:

The correct option is C -4, -2, 0, +2, +4H=+1 Cl=−1CH4 CH3Cl CH2Cl2x+4=0 x+3−1=0 x+2−2=0___________ ___________ ______________x=−4 x=−2 x=0CHCl3 CCl4x+1−3=0 x−4=0____________ _____________x=+2 x=+4

The oxidation number of C in $C H_{4}, C H_{3} C l, C H_{2} C l_{2}, C H C l_{3}$ and $C C l_{4}$ is respectively:

The correct option is C -4, -2, 0, +2, +4
$H = + 1$ $C l = - 1$

$C H_{4}$ $C H_{3} C l$ $C H_{2} C l_{2}$
$x + 4 = 0$ $x + 3 - 1 = 0$ $x + 2 - 2 = 0$
_____ _ __________
$x = - 4$ $x = - 2$ $x = 0$

$C H C l_{3}$ $C C l_{4}$
$x + 1 - 3 = 0$ $x - 4 = 0$
_
$x = + 2$ $x = + 4$