The oxidation number of $C$ in $H N C$ is :

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Solution

The correct option is A 2
The oxidation number of C in HNC is +2.
There is a tripple bond between C and N out of which one bond is coordinate bond and N atom is the donor atom.
Since, the donor atom is more electronegative than acceptor atom, each atom is given 0 oxidation state for the coordinate bond.
For two covalent bonds between C and N, the less electronegative atom is given +1 oxidation number for each covalent bond and N atom is given -1 oxidation number for each covalent bond.

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The oxidation number of C in HNC is :

The oxidation number of $C$ in $H N C$ is :