The oxidation number of cobalt in $K [C o (C O)_{4}]$ is:

- 1

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- 3

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+ 1

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+ 3

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Solution

The correct option is B $- 1$
The oxidation number of colbalt in $K [C o (C O)_{4}]$ is:

$+ 1 + x + 0 \times 4 = 0$

$∴ x = - 1$ .

Hence, option $A$ is correct.

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