The oxidation number of cobalt in $K [C o (C O)_{4}]$ is___________.

+ 1

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+ 3

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- 1

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- 3

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Solution

The correct option is C $- 1$
Oxidation number of $K$ is +1 and $C O$ is 0.
Let oxidation number of $C o$ is $x$ ,
$1 + (x + 4 (0)) = 0$
$x = - 1$
Oxidation number of $C o$ is $- 1$ .

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